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1. A camel merchant willed his 17 camels to hYou have a digital clock that shows only hours and minutes. How many different readings between 11:00 a.m. and 5:00 p.m. (of the same day) contain at least two 2s in the time?<\/p>\n\n\n\n
Hint: <\/strong>Try a smaller problem (less hours)<\/p>\n\n\n\nAnswer<\/summary>\nAnswer\/solution: 34.
There is one such reading between 11:00 and 12:00, 1:00 and 2:00, 3:00 and 4:00, and 4:00 and 5:00 each of which being 22 minutes past the hour. There are 15 such readings between each of 12:00 and 1:00 and 2:00 and 3:00. 12:2X accounts for 10 of them, while 12:02, 12:12, 12:32, 12:42, and 12:52 account for five. 2:2X accounts for 10 of them, while 2:02, 2:12, 2:32, 2:42, and 2:52 account for five as well. The total reading is 1 + 1 + 1 + 1 + 10 + 5 + 10 + 5 = 34.<\/p>\n<\/details>\n<\/div>\n\n\n\n
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\n- Start with a square piece of paper. Draw the largest circle possible inside the square, cut it out and discard the trimmings. Draw the largest square possible inside the circle, cut the square out and discard the trimmings. What fraction of the original square piece of paper has been cut off and thrown away?<\/li>\n<\/ol>\n\n\n\n
Hint: Try the problem with scissors and paper? What do you notice?<\/p>\n\n\n\nAnswer<\/summary>\nAnswer\/solution: Half the area.
Try it yourself. The following diagram shows the results. B is the midpoint of AC, and D is the midpoint of CE. Since BG is congruent to CD and DG is congruent to BC, triangle BCD is congruent to BGD (they also share side BD) by SSS. Therefore the cut-away portion (triangle BCD) of square BCDG is half of the square. This is the same for each portion of the original square. See Figure 9.2 below.<\/p>\n<\/details>\n<\/div>\n<\/div>\n\n\n\n